Meta interview question
fizz-buzz problem
Interview Answer
Anonymous
11 Jan 2017
var fizzBuzz = function(n) { var outArray = []; for(i=1; i<=n; i++) { if(i%15 === 0) { outArray.push("FizzBuzz"); continue; } if(i%3 === 0) { outArray.push("Fizz"); continue; } if(i%5 === 0) { outArray.push("Buzz"); continue; } outArray.push(i.toString()); } return outArray; };